PE has been out of stock on the 4 ohm 20 watt resistor for a LONG time. I've tried to order twice in the last 2 months.
Would the 2 ohm 20 watt be ok? What other values would work for the application?
Other sources?
Here's a question: If you wire 2- 8 ohm resistors in parallel, do you get 4 ohms? Does the power handling stay the same?
What about 2- 2ohm in series? Do you get 4? Power handling?
Bill: Resistors...Parts Express
These calculations can be extended to more than two resistors, as well.
Parallel Connection
Two resistors in Parallel have a Total Resistance equal to the Product divided by the Sum of their individual resistances:
R1 x R2
---------- = R(Parallel Total)
R1 + R2
8 x 8
------ = 4 Ohms
8 + 8
The Total Power Handling for Parallel connection is equal to all the individual Power Ratings added together.
P(R1) + P(R2) = P(Parallel Total)
20W + 10W = 30W
Series Connection
Two resistors in Series have a Total Resistance equal to the Sum of the individual resistances:
R1 + R2 = R(Total)
2 + 2 = 4 Ohms
The Total Power Handling for Series connection is equal to the Lowest individual resistor's Power Rating. If you put a 20W in series with a 10W, your Total Power rating would be 10W, since all the power has to flow through each resistor.
P(Series Total) = Whichever is Lowest of P(R1) or P(R2)
Take Care,
David
Parallel Connection
Two resistors in Parallel have a Total Resistance equal to the Product divided by the Sum of their individual resistances:
R1 x R2
---------- = R(Parallel Total)
R1 + R2
8 x 8
------ = 4 Ohms
8 + 8
The Total Power Handling for Parallel connection is equal to all the individual Power Ratings added together.
P(R1) + P(R2) = P(Parallel Total)
20W + 10W = 30W
Series Connection
Two resistors in Series have a Total Resistance equal to the Sum of the individual resistances:
R1 + R2 = R(Total)
2 + 2 = 4 Ohms
The Total Power Handling for Series connection is equal to the Lowest individual resistor's Power Rating. If you put a 20W in series with a 10W, your Total Power rating would be 10W, since all the power has to flow through each resistor.
P(Series Total) = Whichever is Lowest of P(R1) or P(R2)
Take Care,
David
- Bill Fitzmaurice
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