I do.Seth wrote: ↑Sun Jul 04, 2021 6:19 pm You're completely right Grant. I did say "assuming", however it wasn't a blind assumption. I intentionally ruled that out of the equation for the sake of conversation. It's intended as part of the construct of a hypothetical situation. And you're right that it's real and matters. But, it's not impossible for a 3 way system to have nearly identical impedances at some point in each drivers bandwidth.
For instance, this plot is essentially 4.5Ω at 60Hz, 600Hz, and 6000Hz.
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Are you seeing the logic in my line of inquisition? It's still not making complete sense to me. I'm still in a state of quandary. Does it make sense to you?
I wonder if you considered when looking at the chart you put up, that what you're looking at is the sum of impedance across the cabs bandwidth.
I know you're simplifying it for the sake of discussion, but it's also around 4.5ohms at 150Hz and 10K as examples.
Go back a step.
Look at each driver chart in the three way system. You will see that each chart contributes to the "sum" chart.
So, one could extend the immutable fact "impedance is frequency dependent" further to: "impedance is frequency dependent, but different drivers may/will/do have different impedance at the same frequency".
Other than that, impedance is resistance and reactance. It's reactance that alters impedance on a frequency dependent basis, not resistance. Resistance stays the same regardless of frequency.
To alter power in P = I x V, you would need to alter the value of 1 item in V = I x R to do that. So, if resistance stays the same , and current is constant, V can't change. Current is already constant, and so is voltage, so power stays the same...